Question

question 16 of 25
what is the current flowing through the circuit shown? (v = 110 v, r₁ = 20 ω, r₂ = 30 ω, r₃ = 10 ω) (ohms law: v = ir)

a. 0.55 a
b. 20 a
c. 1.8 a
d. 0.05 a

Explanation:

Step1: Calculate total resistance

Since the resistors are in series, $R_{total}=R_1 + R_2+R_3$. Substituting the given values: $R_{total}=20\Omega + 30\Omega+10\Omega=60\Omega$.

Step2: Use Ohm's law to find current

Ohm's law is $V = IR$. Rearranging for $I$, we get $I=\frac{V}{R}$. Given $V = 110V$ and $R = R_{total}=60\Omega$, then $I=\frac{110V}{60\Omega}\approx1.8A$.

Answer:

C. 1.8 A