Question

question 16 (1 point) \
evaluate $3b^2 + 2d$ when b = 3 and d = 2. \
22 \
31 \
55 \
13

Explanation:

Step1: Substitute b and d values

Substitute \( b = 3 \) and \( d = 2 \) into \( 3b^2 + 2d \).
We get \( 3\times(3)^2 + 2\times2 \).

Step2: Calculate exponent first

Calculate \( (3)^2 = 9 \).
Now the expression becomes \( 3\times9 + 2\times2 \).

Step3: Perform multiplication

Calculate \( 3\times9 = 27 \) and \( 2\times2 = 4 \).
The expression is now \( 27 + 4 \).

Step4: Perform addition

Add \( 27 + 4 = 31 \).

Answer:

31