Question

question 21 of 30 what is the current in a circuit that is powered by a 6.0 v battery and connected in series by a 2.0 ω resistor and a 12.0 ω resistor? a. 0.50 a b. 84.0 a c. 0.43 a d. 3.0 a

Explanation:

Step1: Calculate total series resistance

$R_{\text{total}} = 2.0\ \Omega + 12.0\ \Omega = 14.0\ \Omega$

Step2: Apply Ohm's Law for current

$I = \frac{V}{R_{\text{total}}} = \frac{6.0\ \text{V}}{14.0\ \Omega} \approx 0.43\ \text{A}$

Answer:

C. 0.43 A