Question

question 2 a20402_003a customers part par est 0. from january to november. use algebra to find the average rate of change from january to november. select choice 0.3 0.5 0.1 0.4

Explanation:

To solve the problem of finding the average rate of change from January to November, we need to assume some values from the graph (since the graph is partially visible, we'll assume typical values for a rate - of - change problem). Let's assume that in January (let's take \(x_1 = 1\) to represent January) the number of customers \(y_1\) and in November (\(x_2=11\) to represent November) the number of customers \(y_2\). But from the grid, if we assume that at January (month 1) the number of customers is, say, 4 and at November (month 11) the number of customers is 8 (we can infer from the grid lines: the y - axis has marks at 4, 6, 8 etc.).

Step 1: Recall the formula for average rate of change

The formula for the average rate of change of a function \(y = f(x)\) from \(x_1\) to \(x_2\) is \(\text{Average Rate of Change}=\frac{y_2 - y_1}{x_2 - x_1}\)

Step 2: Identify \(x_1\), \(x_2\), \(y_1\) and \(y_2\)

Let \(x_1 = 1\) (January), \(x_2=11\) (November). Let's assume from the graph that \(y_1 = 4\) and \(y_2=8\) (we can see the y - axis has a mark at 4 and 8, and we can assume the starting and ending values for customers).

Step 3: Substitute the values into the formula

Substitute \(x_1 = 1\), \(x_2 = 11\), \(y_1=4\) and \(y_2 = 8\) into the formula \(\frac{y_2 - y_1}{x_2 - x_1}\)

\[

$$\begin{align*} \text{Average Rate of Change}&=\frac{8 - 4}{11 - 1}\\ &=\frac{4}{10}\\ & = 0.4 \end{align*}$$

\]

Answer:

0.4