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Question
question
in the diagram below of triangle fgh, i is the midpoint of \\(\overline{fh}\\) and j is the midpoint of \\(\overline{gh}\\). if \\(ij = -7x + 44\\), and \\(fg = 28 + 6x\\), what is the measure of \\(\overline{ij}\\)?
answer attempt 1 out of 2
\\(ij = \square\\)
Step1: Apply Midline Theorem
In triangle \(FGH\), \(I\) is the midpoint of \(\overline{FH}\) and \(J\) is the midpoint of \(\overline{GH}\). By the Midline Theorem (also known as the Midsegment Theorem), the segment connecting the midpoints of two sides of a triangle is parallel to the third side and half its length. So, \(IJ=\frac{1}{2}FG\).
Step2: Set up the equation
We know \(IJ = -7x + 44\) and \(FG = 28 + 6x\). Substitute these into the midline theorem equation:
\[
-7x + 44=\frac{1}{2}(28 + 6x)
\]
Step3: Solve for \(x\)
First, multiply both sides by 2 to eliminate the fraction:
\[
2(-7x + 44)=28 + 6x
\]
\[
-14x + 88 = 28 + 6x
\]
Add \(14x\) to both sides:
\[
88=28 + 20x
\]
Subtract 28 from both sides:
\[
60 = 20x
\]
Divide both sides by 20:
\[
x = 3
\]
Step4: Find the length of \(IJ\)
Substitute \(x = 3\) into the expression for \(IJ\):
\[
IJ=-7(3)+44
\]
\[
IJ=-21 + 44
\]
\[
IJ = 23
\]
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\(IJ = 23\)