Question

question
find the volume of a right circular cone that has a height of 6 ft and a base with a radius of 9.7 ft.
round your answer to the nearest tenth of a cubic foot.

Explanation:

Step1: Recall the formula for the volume of a cone

The volume \( V \) of a right circular cone is given by the formula \( V=\frac{1}{3}\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cone.

Step2: Substitute the given values into the formula

We are given that \( r = 9.7\) ft and \( h=6\) ft. Substituting these values into the formula, we get:
\( V=\frac{1}{3}\times\pi\times(9.7)^{2}\times6 \)
First, calculate \( (9.7)^{2}=94.09 \). Then, multiply by 6: \( 94.09\times6 = 564.54 \). Then, multiply by \( \frac{1}{3} \): \( \frac{1}{3}\times564.54=188.18 \). Then, multiply by \( \pi \) (using \( \pi\approx3.14159 \)): \( V = 188.18\times3.14159\approx591.2 \) (rounded to the nearest tenth).

Answer:

\( 591.2 \) cubic feet