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Question
question
the following frequency table summarizes a set of data. what is the five - number summary?
| value | frequency |
|---|---|
| 13 | 1 |
| 14 | 1 |
| 15 | 4 |
| 17 | 5 |
| 18 | 2 |
| 19 | 3 |
| 21 | 1 |
select the correct answer below:
○ min:12, q1:14, median:16, q3:18, max:21
○ min:12, q1:15, median:17, q3:18, max:21
○ min:12, q1:15, median:18, q3:20, max:21
○ min:12, q1:13, median:14, q3:20, max:21
○ min:12, q1:15, median:16, q3:18, max:21
Step1: Find total number of data points
First, we calculate the total number of data points by summing the frequencies.
The frequencies are 2, 1, 1, 4, 5, 2, 3, 1.
So, \(2 + 1 + 1 + 4 + 5 + 2 + 3 + 1 = 19\) data points.
Step2: Determine Min and Max
The minimum value (Min) is the smallest value in the data, which is 12.
The maximum value (Max) is the largest value, which is 21.
Step3: Find the Median (middle value)
Since there are 19 data points (odd number), the median is the \(\frac{19 + 1}{2}=10^{th}\) value when the data is ordered.
Now, we build the cumulative frequency:
- Value 12: cumulative frequency \(2\)
- Value 13: cumulative frequency \(2 + 1 = 3\)
- Value 14: cumulative frequency \(3 + 1 = 4\)
- Value 15: cumulative frequency \(4 + 4 = 8\)
- Value 17: cumulative frequency \(8 + 5 = 13\) (since the 10th value falls here, the median is 17? Wait, no, wait. Wait, let's list the positions:
Wait, let's list the data in order with their frequencies:
- 12 (2 times): positions 1, 2
- 13 (1 time): position 3
- 14 (1 time): position 4
- 15 (4 times): positions 5, 6, 7, 8
- 17 (5 times): positions 9, 10, 11, 12, 13
- 18 (2 times): positions 14, 15
- 19 (3 times): positions 16, 17, 18
- 21 (1 time): position 19
Wait, the 10th position is within the 17s (since after 15, we have 8 cumulative, then 17 starts at position 9). So the 10th value is 17. Wait, but let's check again. Wait, cumulative frequency:
After 12: 2
After 13: 3
After 14: 4
After 15: 8
After 17: 8 + 5 = 13. So the 9th, 10th, 11th, 12th, 13th values are 17. So the median (10th value) is 17.
Step4: Find Q1 (25th percentile)
Q1 is the median of the lower half of the data. The lower half is the first \(\frac{19 - 1}{2}=9\) values? Wait, no. For a dataset with n = 19, the lower half is the first 9 values (since the median is the 10th, so the lower half is positions 1 - 9). Wait, no, the formula for Q1 is the value at the \(\frac{n + 1}{4}\)th position when n is odd? Wait, alternatively, for n = 19, the position of Q1 is \(\frac{19 + 1}{4}=5^{th}\) value? Wait, no, let's use the cumulative frequency.
Wait, the lower half: we have 19 data points. The lower half is the first 9 data points? Wait, no, the median is at position 10, so the lower half is positions 1 - 9, and the upper half is positions 11 - 19.
So for Q1, we need the median of the lower half (positions 1 - 9). Let's list the cumulative frequency up to position 9:
- 12: 2 (positions 1 - 2)
- 13: 3 (position 3)
- 14: 4 (position 4)
- 15: 8 (positions 5 - 8)
- 17: 9 (position 9, since 8 + 1 = 9? Wait, no, the frequency of 17 is 5, so after 15 (cumulative 8), the next values (positions 9 - 13) are 17. Wait, position 9 is the first 17. So the lower half is positions 1 - 9. Let's list the values:
Positions 1 - 2: 12
Position 3: 13
Position 4: 14
Positions 5 - 8: 15 (four times)
Position 9: 17
Wait, so the lower half has 9 values. The median of 9 values is the 5th value (since \(\frac{9 + 1}{2}=5\)). So the 5th value:
Positions 1 - 2: 12 (2)
Position 3: 13 (1)
Position 4: 14 (1)
Positions 5 - 8: 15 (4) → so the 5th value is 15. So Q1 is 15.
Step5: Find Q3 (75th percentile)
Q3 is the median of the upper half of the data. The upper half is positions 11 - 19 (since the median is at position 10, so upper half is positions 11 - 19, which is 9 values). Let's list the upper half:
Positions 11 - 13: 17 (three values, since position 9 - 13 are 17)
Position 14 - 15: 18 (two values)
Positions 16 - 18: 19 (three values)
Position 19: 21 (one value)
Wait, the upper half is positions 11 - 19 (9 va…
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B. Min: 12, Q1: 15, Median: 17, Q3: 18, Max: 21 (assuming the second option is labeled B as per the options, but in the given options, the second one is:
Min
Q1
Median
Q3
Max
12
15
17
18
21
So the correct answer is this option (the second one in the list).