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Question
question
go step by step to reduce the radical.
\\(\sqrt{48}\\)
\\(\sqrt{16}\cdot\sqrt{3}\\)
\\(\square\sqrt{\square}\\)
Step1: Simplify $\sqrt{16}$
We know that $16 = 4\times4$, so $\sqrt{16}=\sqrt{4\times4} = 4$.
Step2: Substitute back
We had $\sqrt{16}\cdot\sqrt{3}$, and since $\sqrt{16} = 4$, this becomes $4\sqrt{3}$.
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$4\sqrt{3}$ (So the first box is 4 and the second box is 3)