Question

question 9 (1 point)

1. $^{31}_{13}\text{al} \

ightarrow ^{0}_{-1}\text{e} + ^{31}_{14}\text{si}$

1. $^{241}_{95}\text{am} \

ightarrow ^{4}_{2}\text{he} + ^{237}_{93}\text{np}$

1. $^{235}_{92}\text{u} + ^{1}_{0}\text{n} \

ightarrow ^{90}_{37}\text{rb} + ^{144}_{55}\text{cs} + 2^{1}_{0}\text{n}$

1. $^{1}_{1}\text{h} + ^{2}_{1}\text{h} \

ightarrow ^{3}_{2}\text{he}$

1. $^{114}_{47}\text{ag} \

ightarrow ^{0}_{-1}\text{e} + ^{114}_{48}\text{cd}$

1. $^{8}_{4}\text{be} + ^{4}_{2}\text{he} \

ightarrow ^{12}_{6}\text{c}$

1. $^{235}_{92}\text{u} + ^{1}_{0}\text{n} \

ightarrow ^{94}_{40}\text{zr} + ^{139}_{52}\text{te} + 3^{1}_{0}\text{n}$

1. $^{162}_{76}\text{os} \

ightarrow ^{4}_{2}\text{he} + ^{158}_{74}\text{w}$
the reactions that represent alpha decays are
(you may select more than one answer)
select one or more:

Explanation:

Step1: Define alpha decay

Alpha decay is a radioactive decay where a nucleus emits an alpha particle ($^{4}_{2}\text{He}$), reducing its mass number by 4 and atomic number by 2.

Step2: Scan reactions for alpha emission

Check each reaction for the product $^{4}_{2}\text{He}$ from a single parent nucleus:

• Reaction2: Parent $^{241}_{95}\text{Am}$ emits $^{4}_{2}\text{He}$, forming $^{237}_{93}\text{Np}$ (mass: $241-4=237$, atomic: $95-2=93$).
• Reaction8: Parent $^{162}_{76}\text{Os}$ emits $^{4}_{2}\text{He}$, forming $^{158}_{74}\text{W}$ (mass: $162-4=158$, atomic: $76-2=74$).

Step3: Eliminate non-alpha reactions

Reactions1/5 are beta decay ($^{0}_{-1}\text{e}$ emission), 3/7 are nuclear fission, 4/6 are nuclear fusion.

Answer:

1. $^{241}_{95}\text{Am}

ightarrow ^{4}_{2}\text{He} + ^{237}_{93}\text{Np}$, 8. $^{162}_{76}\text{Os}
ightarrow ^{4}_{2}\text{He} + ^{158}_{74}\text{W}$