Question

question 3 (1 point)
the area of a rectangle with length 2\sqrt{2} units and width \sqrt{2} units
true
false

Explanation:

Step1: Recall area formula

The area formula for a rectangle is $A = l\times w$, where $l$ is the length and $w$ is the width.

Step2: Substitute values

Given $l = 2\sqrt{2}$ and $w=\sqrt{2}$, then $A=2\sqrt{2}\times\sqrt{2}$.

Step3: Simplify the product

$2\sqrt{2}\times\sqrt{2}=2\times2 = 4$ (since $\sqrt{a}\times\sqrt{a}=a$ for $a\geq0$). But the problem just gives the dimensions and not the area value to check against, so we assume it's asking if these are valid dimensions for area - and they are as they are real - valued non - negative lengths for a rectangle. So the statement as presented (just giving dimensions) is True.

Answer:

True