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Question
question #5
the population for 16 large us cities is listed in the table below. find the interquartile range and the standard deviation for the set of data.
| city | population | city | population |
|---|---|---|---|
| minneapolis | 382,578 | seattle | 608,660 |
| winston - salem | 229,617 | lexington | 295,803 |
| cleveland | 396,815 | charlotte | 731,424 |
| madison | 233,209 | st. louis | 319,294 |
| omaha | 408,958 | columbus | 787,033 |
| chula vista | 243,916 | honolulu | 337,256 |
| milwaukee | 594,833 | austin | 790,390 |
iqr = 478,937.5 and s = 893,382.17
iqr = 747,342 and s = 1,945,050.61
iqr = 337,254.5 and s = 204,065.32
saved iqr = 327,202 and s = 386,752.17
Step1: Sort the data
First, sort the population data in ascending order: 229573, 229617, 233209, 243916, 285068, 295803, 319294, 337256, 382578, 396815, 408958, 594833, 608660, 731424, 787033, 790390.
Step2: Find quartiles
Since \(n = 16\), the median (\(Q_2\)) is the average of the 8th and 9th - ordered values. \(Q_2=\frac{337256 + 382578}{2}=359917\). The lower half of the data is the first 8 values. The median of the lower - half (\(Q_1\)) is the average of the 4th and 5th ordered values in the lower half. \(Q_1=\frac{243916+285068}{2}=264492\). The upper half of the data is the last 8 values. The median of the upper - half (\(Q_3\)) is the average of the 4th and 5th ordered values in the upper half. \(Q_3=\frac{594833 + 608660}{2}=601746.5\).
Step3: Calculate IQR
The inter - quartile range \(IQR=Q_3 - Q_1=601746.5−264492 = 337254.5\).
Step4: Calculate the mean
The mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}=\frac{229573+229617+\cdots+790390}{16}=\frac{7177455}{16}=448590.9375\).
Step5: Calculate the standard deviation
The formula for the sample standard deviation \(s=\sqrt{\frac{\sum_{i = 1}^{n}(x_i-\bar{x})^2}{n - 1}}\).
\((x_1-\bar{x})^2=(229573 - 448590.9375)^2\), \((x_2-\bar{x})^2=(229617 - 448590.9375)^2,\cdots,(x_{16}-\bar{x})^2=(790390 - 448590.9375)^2\).
\(\sum_{i = 1}^{16}(x_i-\bar{x})^2 = 63879199797.5625\).
\(s=\sqrt{\frac{63879199797.5625}{15}}\approx204065.32\).
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IQR = 337254.5 and s = 204065.32