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Question
question 2 of 5 select the correct answer from each drop - down menu. using the line segment shown, derive the distance formula. $d^{2}=(3 - (-5))^{2}+$ 3 - 4 -2 - (-1) -2 - 4 -2 + 4 submit
Step1: Recall distance formula concept
The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ in a coordinate - plane is based on the Pythagorean theorem, $d^{2}=(x_2 - x_1)^{2}+(y_2 - y_1)^{2}$.
Step2: Identify coordinates of endpoints
Assume the left - hand point has coordinates $(x_1,y_1)=(-5,4)$ and the right - hand point has coordinates $(x_2,y_2)=(3, - 2)$.
Step3: Substitute into formula for $d^{2}$
For the $x$ - part, we have $(x_2 - x_1)=(3-(-5))$. For the $y$ - part, we have $(y_2 - y_1)=(-2 - 4)$. So $d^{2}=(3-(-5))^{2}+(-2 - 4)^{2}$.
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The second blank should be filled with $-2 - 4$.