Question

question
solve the following quadratic equation for all values of $x$ in simplest form.
$5(x-7)^2=10$
answer attempt 1 out of 2
additional solution no solution
$x= $
$pm$ $sqrt{}$

Explanation:

Step1: Divide both sides by 5

$\frac{5(x-7)^2}{5}=\frac{10}{5}$
Simplifies to: $(x-7)^2=2$

Step2: Take square root of both sides

$\sqrt{(x-7)^2}=\pm\sqrt{2}$
Simplifies to: $x-7=\pm\sqrt{2}$

Step3: Solve for x

$x=7+\sqrt{2}$ and $x=7-\sqrt{2}$

Answer:

$x=7+\sqrt{2}$ and $x=7-\sqrt{2}$