Question

question what is the volume of a sphere with a diameter of 2.8 cm, rounded to the nearest tenth of a cubic centimeter? answer attempt 1 out of 2

Explanation:

Step1: Find the radius

The radius $r$ of a sphere is half of the diameter $d$. Given $d = 2.8$ cm, so $r=\frac{d}{2}=\frac{2.8}{2}=1.4$ cm.

Step2: Use the volume formula

The volume formula for a sphere is $V = \frac{4}{3}\pi r^{3}$. Substitute $r = 1.4$ cm into the formula: $V=\frac{4}{3}\pi(1.4)^{3}$.
First, calculate $(1.4)^{3}=1.4\times1.4\times1.4 = 2.744$. Then $V=\frac{4}{3}\pi\times2.744$.
$V=\frac{4\times2.744\pi}{3}=\frac{10.976\pi}{3}$.
Taking $\pi\approx3.14$, we have $V=\frac{10.976\times3.14}{3}=\frac{34.46464}{3}\approx11.5$ $cm^{3}$.

Answer:

$11.5$