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question
write the equation of the line in fully simplified slope - intercept form.
Step1: Identify slope-intercept form
The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.
Step2: Find the y - intercept ($b$)
The line crosses the y - axis at $(0,7)$, so $b = 7$.
Step3: Calculate the slope ($m$)
We can use two points on the line. Let's take $(0,7)$ and $(4,10)$. The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$.
Substituting $x_1 = 0,y_1 = 7,x_2 = 4,y_2 = 10$ into the formula:
$m=\frac{10 - 7}{4 - 0}=\frac{3}{4}$? Wait, no, let's check another pair. Let's take $(0,7)$ and $(- 8,1)$. Then $m=\frac{1 - 7}{-8 - 0}=\frac{-6}{-8}=\frac{3}{4}$? Wait, no, wait the line passes through $(0,7)$ and when $x = 4$, $y = 10$? Wait, no, looking at the graph, when $x = 0$, $y = 7$; when $x = 4$, $y = 10$? Wait, no, let's count the rise over run. From $(0,7)$ to $(4,10)$, the rise is $10 - 7=3$, run is $4 - 0 = 4$, so slope is $\frac{3}{4}$? Wait, no, wait another point: when $x=-8$, $y = 1$. So from $(0,7)$ to $(-8,1)$, the change in $y$ is $1 - 7=-6$, change in $x$ is $-8 - 0=-8$, so $\frac{-6}{-8}=\frac{3}{4}$. Wait, but let's check the x - intercept. The line crosses the x - axis at $(-\frac{28}{3},0)$? No, wait, when $y = 0$, $0=mx + 7$, $x=-\frac{7}{m}$. If $m=\frac{3}{4}$, then $x =-\frac{7}{\frac{3}{4}}=-\frac{28}{3}\approx - 9.33$, but the graph shows the line crossing the x - axis at $x=-10$? Wait, maybe I made a mistake. Wait, let's take two points: $(0,7)$ and $(-8,1)$. So $m=\frac{1 - 7}{-8 - 0}=\frac{-6}{-8}=\frac{3}{4}$? Wait, no, wait the distance between $(0,7)$ and $(-8,1)$: the vertical change is $1 - 7=-6$, horizontal change is $-8 - 0=-8$, so slope is $\frac{-6}{-8}=\frac{3}{4}$. Wait, but when $x = 4$, $y=7+\frac{3}{4}\times4=7 + 3=10$, which matches the point $(4,10)$ on the graph. And when $x=-8$, $y=7+\frac{3}{4}\times(-8)=7-6 = 1$, which matches $( - 8,1)$. So the slope $m=\frac{3}{4}$ and $b = 7$.
Wait, no, wait the correct way: the slope - intercept form is $y=mx + b$. We know $b = 7$ (y - intercept). Now, let's find the slope. Let's take two points: $(0,7)$ and $(4,10)$. The slope $m=\frac{10 - 7}{4 - 0}=\frac{3}{4}$. Wait, but let's check the line. From $(0,7)$ to $(4,10)$, that's a rise of 3 and run of 4. So the equation should be $y=\frac{3}{4}x+7$? Wait, no, wait when $x=-8$, $y=\frac{3}{4}\times(-8)+7=-6 + 7 = 1$, which is correct. And when $x = 0$, $y = 7$, correct. So the equation is $y=\frac{3}{4}x + 7$? Wait, no, wait the graph: let's check the point $(4,10)$: $\frac{3}{4}\times4+7=3 + 7 = 10$, correct. The point $(-8,1)$: $\frac{3}{4}\times(-8)+7=-6 + 7 = 1$, correct. So the slope is $\frac{3}{4}$ and y - intercept is 7.
Wait, but wait, maybe I misread the graph. Let's look again. The line passes through $(0,7)$, and when $x = 4$, $y = 10$; $x=-8$, $y = 1$. So the slope is $\frac{10 - 7}{4 - 0}=\frac{3}{4}$. So the equation is $y=\frac{3}{4}x+7$? Wait, no, wait the x - intercept: when $y = 0$, $0=\frac{3}{4}x+7$, $\frac{3}{4}x=-7$, $x=-\frac{28}{3}\approx - 9.33$, but the graph shows the line crossing the x - axis near $x=-10$, which is close to $-\frac{28}{3}\approx - 9.33$? Maybe the graph is a bit approximate. So the slope - intercept form is $y=\frac{3}{4}x + 7$? Wait, no, wait I think I made a mistake. Wait, let's take another pair of points. Let's take $(0,7)$ and $( - 8,1)$. The slope is $\frac{1 - 7}{-8 - 0}=\frac{-6}{-8}=\frac{3}{4}$. So the equation is $y=\frac{3}{4}x+7$.
Wait, no, wait the problem is to write the equation in fully simplified slope - intercept form. So $y=\frac{3}{4}x + 7$? Wait, no, wait maybe the…
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$y=\frac{3}{4}x + 7$