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what is the average kinetic energy (in kj mol⁻¹) of a hypothetical gas with molecular weight 46.5 g mol⁻¹ at a temperature of 43.6 °c? do not try to identify the gas.
answer:

Explanation:

Step1: Convert Celsius to Kelvin

The temperature in Celsius $T_C = 43.6^{\circ}C$. The conversion formula from Celsius to Kelvin is $T = T_C+ 273.15$. So $T=(43.6 + 273.15)\text{ K}=316.75\text{ K}$.

Step2: Use the formula for average - kinetic energy

The formula for the average kinetic energy per mole of a gas is $\overline{E}_k=\frac{3}{2}RT$, where $R = 8.314\text{ J mol}^{-1}\text{ K}^{-1}$ is the universal gas constant.
Substitute $R = 8.314\text{ J mol}^{-1}\text{ K}^{-1}$ and $T = 316.75\text{ K}$ into the formula:
$\overline{E}_k=\frac{3}{2}\times8.314\times316.75\text{ J mol}^{-1}$
$\overline{E}_k = 3.94\times10^{3}\text{ J mol}^{-1}$
Convert to kJ/mol: $\overline{E}_k=\frac{3.94\times 10^{3}}{1000}\text{ kJ mol}^{-1}=3.94\text{ kJ mol}^{-1}$

Answer:

$3.94$