QUESTION IMAGE
Question
for questions 19-22, use the figure below.
- what is the name of the shape on the left?
- how many lines of symmetry are there on the shape to the left?
- list all of the degrees of rotational symmetry for the shape to the left.
- how many diagonals does the regular polygon have?
for questions 23-26 draw the following
- draw all lines of symmetry on the square. (square with vertices labeled a, b, c, d)
- draw all the diagonals on the square. (square with vertices labeled a, b, c, d)
- draw all lines of symmetry on the parallelogram. (parallelogram with vertices labeled a, b, c, d)
- draw all diagonals on the parallelogram. (parallelogram with vertices labeled a, b, c, d)
Question 19
The shape on the left is a regular nonagon (9 - sided polygon) as it has 9 equal - length sides and 9 equal - angle vertices.
Step1: Recall the formula for lines of symmetry of a regular polygon
For a regular \(n\) - sided polygon, the number of lines of symmetry is equal to the number of sides \(n\).
Step2: Identify the number of sides of the polygon
The polygon (regular nonagon) has \(n = 9\) sides. So the number of lines of symmetry is 9.
Step1: Recall the formula for rotational symmetry of a regular polygon
The formula for the angle of rotational symmetry of a regular \(n\) - sided polygon is \(\theta=\frac{360^{\circ}}{n}\), and the rotational symmetries are the multiples of this angle.
Step2: Calculate the basic rotational angle
For a regular nonagon, \(n = 9\), so the basic rotational angle \(\theta=\frac{360^{\circ}}{9} = 40^{\circ}\).
Step3: Find all multiples of the basic angle
The multiples of \(40^{\circ}\) within \(360^{\circ}\) (excluding \(360^{\circ}\) as it is the same as \(0^{\circ}\) rotation) are: \(40^{\circ},80^{\circ},120^{\circ},160^{\circ},200^{\circ},240^{\circ},280^{\circ},320^{\circ}\). And including \(360^{\circ}\) (which is equivalent to the identity rotation), but usually we list the non - trivial ones and sometimes \(360^{\circ}\) is considered as well. But the general way is to list the angles \(\theta_k=k\times\frac{360^{\circ}}{n}\) for \(k = 1,2,\cdots,n - 1\) and \(k=n\) (which is \(360^{\circ}\)). So for \(n = 9\), the rotational symmetries are \(40^{\circ},80^{\circ},120^{\circ},160^{\circ},200^{\circ},240^{\circ},280^{\circ},320^{\circ},360^{\circ}\) (or we can say the non - zero rotational symmetries are the multiples of \(40^{\circ}\) up to \(360^{\circ}\)).
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Regular nonagon