Question

a reading of 432 shows on the face of the meter set to the millivolt scale. the reading means

a. 0.432 volt
b. 4.32 volts
c. 43.2 volts
d. 4,320 volts

what could happen if the meter leads were connected to the positive and negative terminals of the battery while the meter and leads were set to read amperes?

a. could blow an internal fuse or damage the meter
b. would read volts instead of amperes
c. would display ol
d. would display 0.00

the highest amount of resistance that can be read by the meter set to the 2 - kω scale is * 10 points

Explanation:

Step1: Convert millivolts to volts

1 millivolt = 0.001 volts. So, 432 millivolts = 432×0.001 volts.
$432\times0.001 = 0.432$ volts.

Step2: Analyze ammeter - battery connection

An ammeter is designed to be connected in - series in a circuit to measure current. Connecting it directly across a battery (in parallel) with the leads can cause a short - circuit. This can blow an internal fuse or damage the meter.

Step3: Determine maximum resistance on 2 - kΩ scale

The 2 - kΩ scale means the maximum value it can measure is 2000 ohms (since 1 kΩ=1000 ohms).

Answer:

1. A. 0.432 volt
2. A. Could blow an internal fuse or damage the meter
3. 2000 ohms