Question

a recipe calls for 2/5 of a pound of chicken for each person. there are 8 people to be fed. the store sells chicken in 5-pound packages. how many packages of chicken are required? how much chicken will be left over? drag these tiles and drop them in the correct blank above 20 pounds 2 2/5 pounds 2 packages 1 4/5 pounds 3 1/5 pounds 1/5 pound 3 packages 1 package

Explanation:

Step1: Calculate total chicken needed

Each person needs $\frac{2}{5}$ pound, 8 people: $8\times\frac{2}{5}=\frac{16}{5}=3\frac{1}{5}$ pounds.

Step2: Determine packages required

Each package is 5 pounds? Wait, no, wait the problem says "5 - pound packages"? Wait, no, wait the calculation: total needed is $3\frac{1}{5}$ pounds. Wait, no, wait maybe I misread. Wait, the recipe calls for $\frac{2}{5}$ of a pound per person, 8 people. So total chicken needed: $8\times\frac{2}{5}=\frac{16}{5}=3.2$ pounds. The store sells in 5 - pound packages? Wait, no, maybe the package is 5 pounds? Wait, no, the tiles have "3 packages", "2 packages", etc. Wait, no, maybe the package is 5 pounds? Wait, no, let's recalculate. Wait, per person $\frac{2}{5}$ lb, 8 people: $8\times\frac{2}{5}=\frac{16}{5}=3\frac{1}{5}$ lb. Now, how many 5 - pound packages? Wait, no, maybe the package is 5 pounds? Wait, no, the tiles have "20 pounds" (no), "2 2/5 pounds" (no), "3 1/5 pounds" (total needed). Then packages: since each package is 5 pounds? Wait, no, maybe the package is 5 pounds? Wait, no, the total needed is $3\frac{1}{5}$ lb, so we need 1 package? No, wait, maybe the package is 5 pounds? Wait, no, the problem says "5 - pound packages"? Wait, no, maybe I made a mistake. Wait, per person $\frac{2}{5}$ lb, 8 people: $8\times\frac{2}{5}=\frac{16}{5}=3.2$ lb. Now, if packages are 5 lb each, then we need 1 package (since 1 package is 5 lb, which is more than 3.2 lb). But the tiles have "3 packages", "2 packages", "1 package". Wait, maybe the package is 5 lb? Wait, no, maybe the recipe is $\frac{2}{5}$ per person, 8 people: total is $\frac{16}{5}=3\frac{1}{5}$ lb. Then, number of packages: since each package is 5 lb, we need 1 package? But the tiles have "1 package" as an option. Then leftover: 5 - $3\frac{1}{5}=1\frac{4}{5}$? Wait, no, the tiles have "1 4/5 pounds" (which is $\frac{9}{5}$) and "1/5 pound". Wait, maybe I misread the per - person amount. Wait, maybe it's $2\frac{2}{5}$ per person? No, the problem says "2/5 of a pound". Wait, let's check the tiles again. The first blank: "How many packages of chicken are required?" The tiles for packages: 1 package, 2 packages, 3 packages. The total chicken needed is $3\frac{1}{5}$ pounds (from $8\times\frac{2}{5}$). Now, if each package is 5 pounds, we need 1 package (since 1 package is 5 lb, which is enough for $3\frac{1}{5}$ lb). Then leftover: $5 - 3\frac{1}{5}=1\frac{4}{5}$ pounds (which is $1\frac{4}{5}$ pounds, one of the tiles). Wait, but let's re - do:

Step1: Total chicken needed

Number of people = 8, chicken per person = $\frac{2}{5}$ lb.
Total chicken = $8\times\frac{2}{5}=\frac{16}{5}=3\frac{1}{5}$ lb.

Step2: Number of packages

Each package is 5 lb? Wait, no, maybe the package is 5 lb? Wait, the tiles have "1 package" as an option. So we need 1 package (since $3\frac{1}{5}$ lb < 5 lb, so 1 package is enough).

Step3: Leftover chicken

Package size (5 lb) - total needed ($3\frac{1}{5}$ lb) = $5 - 3\frac{1}{5}=1\frac{4}{5}$ lb (which is $1\frac{4}{5}$ pounds, one of the tiles). Wait, but the tiles also have "1/5 pound". Wait, maybe I messed up the per - person amount. Wait, maybe the recipe is $2\frac{2}{5}$ per person? No, the problem says "2/5 of a pound". Wait, let's check the tiles again. The first blank (packages): options are 1 package, 2 packages, 3 packages. The total needed is $3\frac{1}{5}$ lb. So if each package is 5 lb, 1 package is needed. Then leftover is $5 - 3\frac{1}{5}=1\frac{4}{5}$ lb.

Wait, but maybe the package is 5 lb? Let's confirm:

Total chicken needed: $8\times\frac{2}{5}=\frac{16}{5}=3\frac{1}{5}$ lb.

Number of packages: since we can't buy a fraction of a package (assuming we have to buy whole packages), and 1 package (5 lb) is enough (since $3\frac{1}{5}<5$), so 1 package.

Leftover: $5 - 3\frac{1}{5}=1\frac{4}{5}$ lb.

Now, checking the tiles:

For "How many packages of chicken are required?": the tile "1 package".

For "How much chicken will be left over?": the tile "1 4/5 pounds" (which is $1\frac{4}{5}$ pounds) or "1/5 pound"? Wait, no, $5 - 3\frac{1}{5}=1\frac{4}{5}=\frac{9}{5}$, and $3\frac{1}{5}=\frac{16}{5}$, $5=\frac{25}{5}$, so $\frac{25}{5}-\frac{16}{5}=\frac{9}{5}=1\frac{4}{5}$. So the leftover is $1\frac{4}{5}$ pounds, and packages needed is 1 package.

Wait, but let's check again. Maybe the per - person amount is $\frac{2}{5}$ of a pound, 8 people: $8\times\frac{2}{5}=\frac{16}{5}=3\frac{1}{5}$ lb. Packages: 1 package (since 1 package is 5 lb, which is more than $3\frac{1}{5}$ lb). Leftover: $5 - 3\frac{1}{5}=1\frac{4}{5}$ lb.

So:

First blank (packages): 1 package.

Second blank (leftover): $1\frac{4}{5}$ pounds (which is $1\frac{4}{5}$ pounds, one of the tiles).

Answer:

For "How many packages of chicken are required?": 1 package.

For "How much chicken will be left over?": $1\frac{4}{5}$ pounds.