Question

a rectangular block of copper metal weighs 1896 g. the dimensions of the block are 8.4000 cm by 5.5000 cm by 4.6000 cm. from this data, what is the density of copper? round to the hundredths place.

Explanation:

Step1: Calcular el volumen del bloque

El volumen $V$ de un rectángulo es $V = l\times w\times h$, donde $l = 8.4000$ cm, $w = 5.5000$ cm y $h = 4.6000$ cm.
$$V=8.4000\times5.5000\times4.6000 = 212.52\ cm^{3}$$

Step2: Calcular la densidad

La densidad $
ho$ se define como $
ho=\frac{m}{V}$, donde $m = 1896$ g y $V = 212.52\ cm^{3}$.

$$ ho=\frac{1896}{212.52}\approx8.92\ g/cm^{3}$$

Answer:

$8.92\ g/cm^{3}$