Question

1. reflect figure opqr over the x - axis. record the coordinates for p’. (-3,-2) 10. translate figure stuv 7 units down and 5 units left. record the coordinates for t’. (-1,0)

Explanation:

Step1: Recall reflection rule over x - axis

The rule for reflecting a point $(x,y)$ over the x - axis is $(x,-y)$.

Step2: Identify original coordinates of P

Assume from the graph, the coordinates of point P are $(-3,2)$.

Step3: Apply reflection rule

Applying the rule $(x,-y)$ to $(-3,2)$, we get $(-3,-2)$.

for second part:

Step1: Recall translation rule

The rule for translating a point $(x,y)$ 7 units down and 5 units left is $(x - 5,y - 7)$.

Step2: Identify original coordinates of T

Assume from the graph, the coordinates of point T are $(4,7)$.

Step3: Apply translation rule

For $x = 4$ and $y = 7$, we have $x-5=4 - 5=-1$ and $y - 7=7 - 7 = 0$. So the new coordinates of $T'$ are $(-1,0)$.

Answer:

$(-3,-2)$