Question

1. reflect the quadrilateral over the line y = -x. p(-4, 4), q(0, 6), r(3, -1), s(-2, 5)
2. reflect the triangle over the line y = -x. a(1, 1), b(-6, 6), c(3, 4)

Explanation:

Step1: Recall reflection rule

The rule for reflecting a point $(x,y)$ over the line $y = -x$ is $(x,y)\to(-y,-x)$.

Step2: Reflect point P

For $P(-4,4)$, applying the rule: $(-4,4)\to(-4,4)$. So $P'(-4,4)$.

Step3: Reflect point Q

For $Q(0,6)$, applying the rule: $(0,6)\to(-6,0)$. So $Q'(-6,0)$.

Step4: Reflect point R

For $R(3,-1)$, applying the rule: $(3,-1)\to(1,-3)$. So $R'(1,-3)$.

Step5: Reflect point S

For $S(-2,5)$, applying the rule: $(-2,5)\to(-5,2)$. So $S'(-5,2)$.

Step6: Reflect point A

For $A(1,1)$, applying the rule: $(1,1)\to(-1,-1)$. So $A'(-1,-1)$.

Step7: Reflect point B

For $B(-6,6)$, applying the rule: $(-6,6)\to(-6,6)$. So $B'(-6,6)$.

Step8: Reflect point C

For $C(3,4)$, applying the rule: $(3,4)\to(-4,-3)$. So $C'(-4,-3)$.

Answer:

$P'(-4,4)$
$Q'(-6,0)$
$R'(1,-3)$
$S'(-5,2)$
$A'(-1,-1)$
$B'(-6,6)$
$C'(-4,-3)$