Question

(a) rewrite as a logarithmic equation.
$6^{-1}=\frac{1}{6}$
$\log_{\square}\square=\square$
(b) rewrite as an exponential equation.
$\log_{4}64=3$
$\square^{\square}=\square$

Explanation:

Step1: Apply log-exponential relation

For $a^b = c$, $\log_a c = b$.
Here $6^{-1}=\frac{1}{6}$, so $\log_{6}\frac{1}{6}=-1$

Step2: Apply log-exponential reverse

For $\log_a c = b$, $a^b = c$.
Here $\log_{4}64=3$, so $4^3=64$

Answer:

(a) $\log_{6}\frac{1}{6}=-1$
(b) $4^3=64$