Question

rewrite using a single positive exponent. \\((6^{5})^{-5}\\)

Explanation:

Step1: Apply power of a power rule

$(a^m)^n = a^{m \times n}$
So, $(6^5)^{-5} = 6^{5 \times (-5)}$

Step2: Calculate the exponent

$5 \times (-5) = -25$, so we get $6^{-25}$

Step3: Convert to positive exponent

$a^{-n} = \frac{1}{a^n}$, so $6^{-25} = \frac{1}{6^{25}}$

Answer:

$\frac{1}{6^{25}}$