Question

rewrite without parentheses.\\((2a^{3}b^{6}-5a^{5})(3ab^{2})\\)\
simplify your answer as much as possible.

Explanation:

Step1: Apply distributive property

Multiply each term in the first parentheses by \(3ab^2\).
\((2a^3b^6)(3ab^2) - (5a^5)(3ab^2)\)

Step2: Multiply coefficients and add exponents of like bases

For the first term: \(2\times3 = 6\), \(a^{3 + 1}=a^4\), \(b^{6+2}=b^8\), so it becomes \(6a^4b^8\).
For the second term: \(5\times3 = 15\), \(a^{5 + 1}=a^6\), so it becomes \(15a^6b^2\).

Answer:

\(6a^4b^8 - 15a^6b^2\)