QUESTION IMAGE
Question
rhombus defg is a translation of rhombus defg. write the translation rule.
(x, y) ↦ (x + , y + )
Step1: Find coordinates of a point
Take point \( D \) and \( D' \). Let's assume \( D \) has coordinates \((-8, -5)\) (from the graph, looking at the purple rhombus) and \( D' \) has coordinates \((4, 7)\). Wait, maybe better to take a clearer point. Let's take point \( E \) and \( E' \). Let's find coordinates: \( E \) is at \((-6, -4)\)? Wait no, looking at the lower rhombus (DEFG), let's see the grid. Let's take point \( D \): from the lower rhombus, \( D \) is at \((-8, -5)\)? Wait maybe I made a mistake. Wait the lower rhombus: let's check the x and y. The lower rhombus (DEFG) has points: let's see, \( D \) is at \((-8, -5)\)? No, maybe better to take \( E \) in DEFG: looking at the lower rhombus, \( E \) is at \((-6, -4)\)? Wait the upper rhombus (D'E'F'G'): \( E' \) is at \((6, 8)\). Wait no, the grid: each square is 1 unit. Let's check the x-coordinate difference and y-coordinate difference. Let's take point \( D \) in DEFG: let's say \( D \) is at \((-8, -5)\)? No, wait the lower rhombus: let's look at the x-axis. The lower rhombus is around x from -8 to -4? Wait no, the upper rhombus is at x from 4 to 8. Wait let's take point \( F \) in DEFG: let's say \( F \) is at \((-4, -5)\) (since it's a rhombus, symmetric). Then \( F' \) is at \((8, 7)\)? Wait no, the upper rhombus \( F' \) is at \((8, 7)\)? Wait no, looking at the graph, \( F' \) is at (8,7)? Wait the upper rhombus: \( D' \) is at (4,7), \( E' \) at (6,8), \( F' \) at (8,7), \( G' \) at (6,6). The lower rhombus: \( D \) at (-8,-5), \( E \) at (-6,-4), \( F \) at (-4,-5), \( G \) at (-6,-6). Wait now, let's calculate the translation for \( D \) to \( D' \): \( D(-8, -5) \) to \( D'(4, 7) \). The change in x: \( 4 - (-8) = 12 \)? No, that can't be. Wait I must have misread the coordinates. Wait the lower rhombus: let's check the y-axis. The lower rhombus is below the x-axis (y negative), upper is above (y positive). Let's take point \( G \) in DEFG: \( G \) is at \((-6, -6)\), and \( G' \) is at \((6, 6)\). Ah! That's a better point. So \( G(-6, -6) \) to \( G'(6, 6) \). Now, calculate the change in x: \( 6 - (-6) = 12 \)? No, wait no, the upper \( G' \) is at (6,6)? Wait the upper rhombus: \( G' \) is at (6,6)? Wait the graph: the upper rhombus, \( G' \) is at (6,6)? Let's check the grid. The y-axis: 0 is the middle. The upper rhombus: \( E' \) is at (6,8), \( D' \) at (4,7), \( F' \) at (8,7), \( G' \) at (6,6). The lower rhombus: \( E \) at (-6,-4), \( D \) at (-8,-5), \( F \) at (-4,-5), \( G \) at (-6,-6). Ah! Now, take \( G(-6, -6) \) and \( G'(6, 6) \). Wait no, \( G' \) is at (6,6)? Wait the y-coordinate of \( G' \) is 6, and \( G \) is at -6. So the change in y: \( 6 - (-6) = 12 \)? No, that's too much. Wait I think I messed up the coordinates. Wait the lower rhombus: let's look at the y-axis. The lower rhombus is at y = -6, -5, -4. The upper at y = 6,7,8. Wait the distance between y = -6 and y = 6 is 12? No, that can't be. Wait maybe the lower rhombus is at y = -5, -4, -6? Wait no, let's count the grid lines. From \( G \) (lower) to \( G' \) (upper): how many units up? Let's see, \( G \) is at (let's check the grid again). Wait the lower rhombus: \( G \) is at ( -6, -6 )? No, the lower rhombus: looking at the graph, the lower rhombus is below the x-axis (y negative), and the upper is above (y positive). Let's take point \( E \) in DEFG: \( E \) is at ( -6, -4 ), and \( E' \) is at ( 6, 8 ). Now, calculate the change in x: \( 6 - (-6) = 12 \)? No, that's 12, but that seems too much. Wait no, maybe the lower rhombus is at ( -8, -5 ), ( -6, -4 ), ( -4, -5 ),…
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\( (x, y) \to (x + 12, y + 12) \)