Question

scarlett went camping with the school outing club. they roasted marshmallows by the campfire every night for 6 nights, consuming: 77 marshmallows 30 marshmallows 85 marshmallows 13 marshmallows 60 marshmallows 47 marshmallows what was the mean absolute deviation of the numbers of marshmallows eaten? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): marshmallows

Explanation:

Step1: Calculate the mean

First, find the sum of the marshmallows: \(77 + 30 + 85 + 13 + 60 + 47 = 312\)
Then, divide by the number of nights (6) to get the mean: \(\frac{312}{6} = 52\)

Step2: Find the absolute deviations

Calculate the absolute difference between each value and the mean:
\(\vert 77 - 52 \vert = 25\)
\(\vert 30 - 52 \vert = 22\)
\(\vert 85 - 52 \vert = 33\)
\(\vert 13 - 52 \vert = 39\)
\(\vert 60 - 52 \vert = 8\)
\(\vert 47 - 52 \vert = 5\)

Step3: Calculate the mean of these absolute deviations

Sum the absolute deviations: \(25 + 22 + 33 + 39 + 8 + 5 = 132\)
Divide by the number of values (6) to get the MAD: \(\frac{132}{6} = 22.0\) (rounded to the nearest tenth)

Answer:

22.0