Question

a scuba diver was 15 feet below sea level. he rose 6 feet. how far below sea level is he now?
which points are located in quadrant iii? select all that apply
\ta) (2, 7)
\tb) (-3, 5)
\tc) (-1, -5)
\td) (-8, -7)
evaluate and simplify.
$4\frac{1}{6}+\frac{2}{4}=$
write an integer to represent each statement.
|an altitude of 300 feet|
|23 feet below sea level|
|a credit of $201|

Explanation:

Step1: Define initial depth

Let sea level = 0, so initial position: $-15$ feet

Step2: Add upward movement

Add the 6 feet rise: $-15 + 6$

Step3: Calculate new depth

$-15 + 6 = -9$
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Step1: Recall Quadrant III rule

Points have $(-x, -y)$ coordinates

Step2: Check each option

a) $(2,7)$: $(+x,+y)$ → Quadrant I
b) $(-3,5)$: $(-x,+y)$ → Quadrant II
c) $(-1,-5)$: $(-x,-y)$ → Quadrant III
d) $(-8,-7)$: $(-x,-y)$ → Quadrant III
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Step1: Convert mixed number to improper

$4\frac{1}{6} = \frac{4\times6 + 1}{6} = \frac{25}{6}$

Step2: Multiply the fractions

$\frac{25}{6} \times \frac{2}{4} = \frac{25 \times 2}{6 \times 4}$

Step3: Simplify the product

$\frac{50}{24} = \frac{25}{12} = 2\frac{1}{12}$
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Step1: Assign positive for altitude

Altitude above sea level: $+300$ or $300$

Step2: Assign negative for below sea level

Below sea level: $-23$

Step3: Assign positive for credit

Credit (positive balance change): $+201$ or $201$

Answer:

1. The diver is 9 feet below sea level, or $-9$ feet.
2. c) $(-1, -5)$, d) $(-8, -7)$
3. $2\frac{1}{12}$ or $\frac{25}{12}$

4.

• An altitude of 300 feet: $300$
• 23 feet below sea level: $-23$
• A credit of $201$: $201$