Question

section 5.2 homework
score: 0/15 answered 0/15
question 1
a bag of m&ms has 4 red, 3 green, 5 blue, and 7 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)
a) a yellow?
b) a blue or green?
c) a red or blue or yellow?

Explanation:

Step1: Calculate total number of M&Ms

$4 + 3+5 + 7=19$

Step2: Calculate probability of picking a yellow

The number of yellow M&Ms is 7. Probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{7}{19}\approx 0.3684$

Step3: Calculate probability of picking a blue or green

Number of blue or green M&Ms is $5 + 3=8$. So $P(\text{blue or green})=\frac{8}{19}\approx 0.4211$

Step4: Calculate probability of picking a red or blue or yellow

Number of red or blue or yellow M&Ms is $4+5 + 7 = 16$. So $P(\text{red or blue or yellow})=\frac{16}{19}\approx 0.8421$

Answer:

a) $0.3684$
b) $0.4211$
c) $0.8421$