Question

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal. the average speed of the buses is equal. the average speed of the buses is not equal. the velocity of the buses is not equal. both buses move with constant velocity the entire trip.

Explanation:

Step1: Recall speed and velocity definitions

Speed is a scalar quantity (only magnitude), velocity is a vector quantity (magnitude and direction).

Step2: Calculate average speed

Average speed = distance/time. Both buses travel 10 miles in 15 minutes. So average - speed = $\frac{10}{15/60}=40$ miles per hour for both. So average speed is equal.

Step3: Analyze velocity

The buses are moving in opposite directions. Velocity has a direction component. So the velocities are not equal.

Step4: Consider constant - velocity condition

We have no information about the motion being non - stop or with constant speed throughout. So we cannot say they move with constant velocity.

Answer:

The average speed of the buses is equal.
The velocity of the buses is not equal.