Question

select the correct answer from each drop-down menu.
on this map, oxford street is perpendicular to ▼ , and rosewood street is perpendicular to ▼ assume that the street intersections form right angles.

Answer:

To solve this, we use the property of perpendicular lines (they form right angles, and in a grid of streets, vertical and horizontal streets are perpendicular).

For Oxford Street:

Oxford Street is a vertical street (runs up - down). Horizontal streets (like Waterloo St, Rosewood St) are perpendicular to vertical streets? No, wait—vertical streets are perpendicular to horizontal streets, and vertical streets are parallel to other vertical streets, horizontal to other horizontal. Wait, looking at the map: George St, Oak St, Oxford St are vertical (run north - south), Waterloo St and Rosewood St are horizontal (run east - west). So a vertical street (Oxford St) is perpendicular to horizontal streets (Waterloo St, Rosewood St) and parallel to other vertical streets (George St, Oak St). Wait, no—perpendicular means they intersect at 90 degrees. So vertical (Oxford St) is perpendicular to horizontal (Waterloo St, Rosewood St). But also, vertical streets: Oxford St is vertical, so it's perpendicular to horizontal streets (Waterloo or Rosewood) and parallel to George/Oak. Wait, the first dropdown: Oxford St (vertical) is perpendicular to which? Let's see the streets: George St (vertical), Oak St (vertical), Oxford St (vertical) are vertical. Waterloo St (horizontal), Rosewood St (horizontal) are horizontal. So a vertical street (Oxford St) is perpendicular to horizontal streets (Waterloo St, Rosewood St) and also, wait—no, vertical and horizontal are perpendicular. Also, vertical streets are parallel to each other, horizontal to each other. Wait, maybe the options (even though not shown, but from the map): the first dropdown for Oxford St (vertical) should be a horizontal street? Wait, no—wait, maybe I got vertical/horizontal wrong. Wait, the map: George St, Oak St, Oxford St are the vertical (north - south) streets, Waterloo and Rosewood are east - west (horizontal). So Oxford St (vertical) is perpendicular to Waterloo St (horizontal) and Rosewood St (horizontal). But also, is there a vertical street? No, Oxford is vertical, so it's perpendicular to horizontal streets. Wait, maybe the first dropdown: Oxford St is perpendicular to Waterloo St (or Rosewood St), and the second: Rosewood St (horizontal) is perpendicular to vertical streets (George St, Oak St, Oxford St).

Assuming the dropdown options for the first blank (Oxford St perpendicular to) are horizontal streets (Waterloo St, Rosewood St) or vertical? No—perpendicular: vertical ⊥ horizontal. So Oxford St (vertical) is perpendicular to Waterloo St (horizontal) or Rosewood St (horizontal). For the second blank: Rosewood St (horizontal) is perpendicular to vertical streets (George St, Oak St, Oxford St).

Let's confirm:

• Perpendicular lines intersect at 90°. In a grid, vertical (north - south) and horizontal (east - west) streets are perpendicular.
• Oxford St is vertical (runs along the same direction as George St, Oak St), so it’s perpendicular to horizontal streets (Waterloo St, Rosewood St).
• Rosewood St is horizontal (runs along the same direction as Waterloo St), so it’s perpendicular to vertical streets (George St, Oak St, Oxford St).

Final Answers (assuming dropdown options):

For the first blank (Oxford St perpendicular to): Waterloo St (or Rosewood St, but likely Waterloo or Rosewood; if options include George/Oak, no—they are parallel). For the second blank (Rosewood St perpendicular to): George St (or Oak St, Oxford St—all vertical).

(Note: Since the dropdown options aren’t visible, but based on the map’s grid, the logical answers are: Oxford St ⊥ Waterloo St (or Rosewood St), Rosewood St ⊥ George St (or Oak St, Oxford St).)