Question

select each parent’s alleles to place them on the punnett square. yy yy

Explanation:

Step1: Analyze Parent Alleles

The yellow parent has alleles \( YY \), so it can only contribute \( Y \) to each gamete. The green parent has alleles \( yy \), so it can only contribute \( y \) to each gamete.

Step2: Fill Top Row (from yy parent)

The top row of the Punnett square (from the \( yy \) parent) will have \( y \) in each cell of the top row. So the top - left and top - right cells of the top row get \( y \) (but we also consider the contribution from the \( YY \) parent). Wait, actually, the Punnett square is filled by taking one allele from each parent. The \( YY \) parent (left) will contribute \( Y \) to each of its two gametes (since it's \( YY \), it can only make \( Y \) gametes). The \( yy \) parent (top) will contribute \( y \) to each of its two gametes (since it's \( yy \), it can only make \( y \) gametes).
So the top - left cell: \( Y \) (from \( YY \)) and \( y \) (from \( yy \)) → \( Yy \)
Top - right cell: \( Y \) (from \( YY \)) and \( y \) (from \( yy \)) → \( Yy \)
Bottom - left cell: \( Y \) (from \( YY \)) and \( y \) (from \( yy \)) → \( Yy \)
Bottom - right cell: \( Y \) (from \( YY \)) and \( y \) (from \( yy \)) → \( Yy \)

To place the alleles on the square: The left - hand side (from \( YY \)) should have \( Y \) in both the left - hand cells (top and bottom of the left column). The top - hand side (from \( yy \)) should have \( y \) in both the top - hand cells (left and right of the top row).

So when filling the square:

• Top - left cell: \( Y \) (from left, \( YY \)) and \( y \) (from top, \( yy \))
• Top - right cell: \( Y \) (from left, \( YY \)) and \( y \) (from top, \( yy \))
• Bottom - left cell: \( Y \) (from left, \( YY \)) and \( y \) (from top, \( yy \))
• Bottom - right cell: \( Y \) (from left, \( YY \)) and \( y \) (from top, \( yy \))

If we are just placing the parent's alleles on the square (the axes of the Punnett square): The left - hand axis (vertical) is for the \( YY \) parent, so we put \( Y \) in the top and bottom of the left - hand column. The top - hand axis (horizontal) is for the \( yy \) parent, so we put \( y \) in the left and right of the top row.

So the Punnett square should be filled as follows:

	\( y \)	\( y \)
\( Y \)	\( Yy \)	\( Yy \)

Answer:

The left - hand (vertical) side of the Punnett square (corresponding to the \( YY \) parent) should have \( Y \) in both the top - left and bottom - left cells of the left column. The top - hand (horizontal) side of the Punnett square (corresponding to the \( yy \) parent) should have \( y \) in both the top - left and top - right cells of the top row. Then the inner cells are filled as \( Yy \) for all four cells.