Question

select an equivalent value, rounded to the nearest tenth, for each given measure.
customary and metric unit equivalents
length\tweight/mass\tcapacity
1 m ≈ 3.28 ft\t1 oz ≈ 28.35 g\t1 gal ≈ 3.79 l
1 m ≈ 39.37 in.\t1 kg ≈ 2.20 lb\t1 qt ≈ 0.95 l
1 in. = 2.54 cm\t1 metric ton (t) ≈ 1.102 t\t
1 mi ≈ 1.61 km\t\t
\t10.2\t15.4\t19.8\t22.7
4 in. ≈ ? cm\t□\t□\t□\t□
6 gal ≈ ? l\t□\t□\t□\t□
7 kg ≈ ? lb\t□\t□\t□\t□
65 ft ≈ ? m\t□\t□\t□\t□

Explanation:

4 in. ≈? cm

Step1: Identify conversion factor

From table, \(1\) in. \(= 2.54\) cm.

Step2: Multiply by 4

\(4\times2.54 = 10.16\)

Step3: Round to nearest tenth

\(10.16\approx10.2\)

6 gal ≈? L

Step1: Identify conversion factor

From table, \(1\) gal \(\approx3.79\) L.

Step2: Multiply by 6

\(6\times3.79 = 22.74\)

Step3: Round to nearest tenth

\(22.74\approx22.7\)

7 kg ≈? lb

Step1: Identify conversion factor

From table, \(1\) kg \(\approx2.20\) lb.

Step2: Multiply by 7

\(7\times2.20 = 15.4\)

65 ft ≈? m

Answer:

• \(4\) in. \(\approx\) \(\boldsymbol{10.2}\) cm (select 10.2)
• \(6\) gal \(\approx\) \(\boldsymbol{22.7}\) L (select 22.7)
• \(7\) kg \(\approx\) \(\boldsymbol{15.4}\) lb (select 15.4)
• \(65\) ft \(\approx\) \(\boldsymbol{19.8}\) m (select 19.8)