Question

1. set maltose, maltase, glucose, and amylase inhibitor to 0. set ph to 7 and temperature to 35.
2. set amylase to 1 mmol.
3. set starch to 2.5 mmol.
4. run the simulation and record the amount of time it takes for all of the starch to be converted to maltose.
5. repeat with amylase set to 2, 3, 4, and 5 mmol.
6. calculate the rate of maltose production by dividing the amount of maltose produced by the time it took to consume all of the starch.

data:

amylase (mmol)	time to consume all starch (sec)	maltose produced (mmol)	rate of maltose production (mmol/sec)
2
3
4
5

Explanation:

Step1: Determine amount of maltose produced

Since 1 mole of starch is converted to 1 mole of maltose, when starch is 2.5 mmol, maltose produced is also 2.5 mmol for each case.

Step2: Calculate rate formula

The rate of maltose production $r=\frac{\text{Maltose produced}}{\text{Time to consume all starch}}$. For each amylase concentration, we need to fill in the time - to - consume value from the experiment and then calculate the rate using this formula. But since the time values are not given in the problem, we can only state the general way to calculate. For example, if for amylase = 1 mmol, the time to consume all starch is $t_1$ seconds, the rate $r_1=\frac{2.5}{t_1}$ mmol/sec. Similarly for amylase = 2 mmol, if the time is $t_2$ seconds, $r_2=\frac{2.5}{t_2}$ mmol/sec and so on.

Answer:

Amylase (mmol)	Time to consume all starch (sec)	Maltose produced (mmol)	Rate of maltose production (mmol/sec)
2	(To be filled from experiment)	2.5	$\frac{2.5}{\text{(Time value from experiment)}}$
3	(To be filled from experiment)	2.5	$\frac{2.5}{\text{(Time value from experiment)}}$
4	(To be filled from experiment)	2.5	$\frac{2.5}{\text{(Time value from experiment)}}$
5	(To be filled from experiment)	2.5	$\frac{2.5}{\text{(Time value from experiment)}}$