Question

	set 1	set 2
mass 1	90 kg	90 kg
mass 2	30 kg	30 kg
distance	3 m	3 m

which set has more gravitational force energy?
remember : $f = \frac{-g(m_1m_2)}{d^2}$
the sets have an equal amount of gravitational force energy.
set 1
set 2

Explanation:

Step1: Analyze the formula for gravitational force

The formula for gravitational force is \( F = \frac{-G(m_1m_2)}{d^2} \). Here, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses, and \( d \) is the distance between them.

Step2: Compare the values for Set 1 and Set 2

For Set 1: \( m_1 = 90\space kg \), \( m_2 = 30\space kg \), \( d = 3\space m \)
For Set 2: \( m_1 = 90\space kg \), \( m_2 = 30\space kg \), \( d = 3\space m \)
Since \( m_1 \), \( m_2 \), and \( d \) are the same for both sets, substituting these values into the formula will give the same gravitational force for both sets. The negative sign indicates the nature of the force (attractive), but the magnitude of the force (and thus the gravitational force energy, considering the relationship between force and energy in a gravitational context) will be equal for both sets.

Answer:

The sets have an equal amount of gravitational force energy.