Question

from the side view, a gymnastics mat forms a right triangle with other angles measuring 60° and 30°. the gymnastics mat extends 5 feet across the floor. how high is the mat off the ground?
10
5√3
\frac{5√3}{3}
\frac{5}{2} ft

Explanation:

Step1: Use tangent function.

\(\tan(60^{\circ})=\frac{h}{5}\), where \(h\) is the height.

Step2: Solve for \(h\).

Since \(\tan(60^{\circ})=\sqrt{3}\), then \(h = 5\sqrt{3}\) ft.

Answer:

B. \(5\sqrt{3}\) ft