Question

simplify. (-32)^(7/5)

Explanation:

Step1: Rewrite the base

$(-32)^{\frac{7}{5}}=((-2)^5)^{\frac{7}{5}}$

Step2: Apply power - of - a - power rule

$((-2)^5)^{\frac{7}{5}}=(-2)^{5\times\frac{7}{5}}$

Step3: Calculate the exponent

$(-2)^{5\times\frac{7}{5}}=(-2)^7$

Step4: Evaluate the power

$(-2)^7=-128$

Answer:

$-128$