Question

simplify.
\frac{8u^{2}v^{4}}{36u^{3}v^{4}}

Explanation:

Step1: Simplify the numerical coefficients

$\frac{8}{36} = \frac{2}{9}$

Step2: Simplify the $u$-terms using exponent rules

$\frac{u^2}{u^3} = u^{2-3} = u^{-1} = \frac{1}{u}$

Step3: Simplify the $v$-terms using exponent rules

$\frac{v^4}{v^4} = v^{4-4} = v^0 = 1$

Step4: Multiply the simplified parts

$\frac{2}{9} \times \frac{1}{u} \times 1$

Answer:

$\frac{2}{9u}$