Question

simplify the expression.
select
ot a real number\ if applicable.
\\(\sqrt4{-16} = \square\\)

Explanation:

Step1: Analyze root parity and sign

For even-indexed roots ($n=4$, even), $\sqrt[n]{x}$ is a real number only if $x\geq0$. Here, $x=-16<0$.

Step2: Conclude result

Since the radicand is negative and the root is even, no real number satisfies the expression.

Answer:

Not a real number