Question

simplify the expression. write the answer using only positive exponents.
\frac{(p^{-2})^0}{3p^{-9}}
\frac{(p^{-2})^0}{3p^{-9}} = \square

Explanation:

Step1: Apply zero - exponent rule

Any non - zero number or expression to the power of 0 is 1. So, \((p^{-2})^0 = 1\). The expression becomes \(\frac{1}{3p^{-9}}\).

Step2: Use negative - exponent rule

The negative - exponent rule states that \(a^{-n}=\frac{1}{a^{n}}\), so \(p^{-9}=\frac{1}{p^{9}}\). Then \(\frac{1}{3p^{-9}}=\frac{p^{9}}{3}\).

Answer:

\(\frac{p^{9}}{3}\)