Question

simplify the following expression.
$(c - 3)^2$
$c^2 + ?c + \square$

Explanation:

Step1: Recall the formula for squaring a binomial

The formula for \((a - b)^2\) is \(a^2 - 2ab + b^2\). In the expression \((c - 3)^2\), we have \(a = c\) and \(b = 3\).

Step2: Apply the formula

Substitute \(a = c\) and \(b = 3\) into the formula:
\[

$$\begin{align*} (c - 3)^2&=c^2-2\times c\times3 + 3^2\\ &=c^2-6c + 9 \end{align*}$$

\]

Answer:

The coefficient of \(c\) is \(-6\) and the constant term is \(9\). So the green box should be filled with \(-6\) and the white box with \(9\). For the coefficient of \(c\) (the green box), the answer is \(-6\).