Question

simplify the radical.
\sqrt{28} = 7\sqrt{2}

Explanation:

Step1: Factor the radicand

Factor 28 into a product of a perfect square and another number: \(28 = 4\times7\)

Step2: Apply square root property

Use the property \(\sqrt{ab}=\sqrt{a}\times\sqrt{b}\) (\(a\geq0,b\geq0\)): \(\sqrt{28}=\sqrt{4\times7}=\sqrt{4}\times\sqrt{7}\)

Step3: Simplify the perfect square root

Since \(\sqrt{4} = 2\), we get: \(2\sqrt{7}\)

Answer:

\(2\sqrt{7}\)