Question

simplify. use positive exponents for any variables.\\(\frac{10x^{-6}yz^{-7}}{5x^{2}yz}\\)\\(\frac{10x^{-6}yz^{-7}}{5x^{2}yz}=\square\\)(simplify your answer. type exponential notation with positive exponents.)

Explanation:

Step1: Simplify the coefficients

$\frac{10}{5} = 2$

Step2: Simplify $x$-terms (subtract exponents)

$x^{-6 - 2} = x^{-8} = \frac{1}{x^8}$

Step3: Simplify $y$-terms (subtract exponents)

$y^{1 - 1} = y^0 = 1$

Step4: Simplify $z$-terms (subtract exponents)

$z^{-7 - 1} = z^{-8} = \frac{1}{z^8}$

Step5: Combine all simplified parts

$2 \times \frac{1}{x^8} \times 1 \times \frac{1}{z^8}$

Answer:

$\frac{2}{x^8 z^8}$