Question

the size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. two cells are measured using this method:

cell g: $7.27 \times 10^{-3}$ centimeters
cell h: $4.3 \times 10^{-4}$ centimeters

how many times larger is the diameter of cell g than the diameter of cell h? write your answer in standard notation, rounding to the nearest tenth.

answer
attempt 1 out of 2

answer:

Explanation:

Step1: Divide Cell G's diameter by Cell H's diameter

To find how many times larger Cell G's diameter is than Cell H's, we divide the diameter of Cell G by the diameter of Cell H. So we have the expression: $\frac{7.27 \times 10^{-3}}{4.3 \times 10^{-4}}$.

Step2: Use the rule of exponents for division ($\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$)

First, divide the coefficients: $\frac{7.27}{4.3}\approx1.6907$. Then, for the exponents, we have $10^{-3-(-4)} = 10^{-3 + 4}=10^{1}$.

Step3: Multiply the results from Step2

Multiply the coefficient result by the exponent result: $1.6907\times10^{1}=16.907$.

Step4: Round to the nearest tenth

Rounding $16.907$ to the nearest tenth gives $16.9$.

Answer:

16.9