Question

skill practice 2
significant figures practice
name: shantelle bennett
date: 9/15/15
hour: 3rd
perform the following operations and give answers with the correct number of significant figures. if the question is in scientific notation, then please use scientific notation in your answer.

1. 200.00 + 125.2 = 325.2

125.2

1. 12,020 + 6006 =
2. 0.003450 + 0.0140 = 0.01745
3. 0.820 - 0.030 =
4. (240,900)(120.0) =
5. 340/12.5 =
6. (2.450×10^6)(2.0×10^6) =
7. (5.369×10^12)/(2.89×10^7) =

Explanation:

Step1: Perform addition for 12.020 + 6006

Add the two numbers: $12.020+6006 = 6018.020$. In addition, the result should be rounded to the least - precise decimal place among the numbers being added. Here, 6006 has no decimal places, so the answer is 6018.

Step2: Perform addition for 0.003450 + 0.0140

Add the two numbers: $0.003450 + 0.0140=0.01745$. Rounding to the least - precise decimal place (4 decimal places for 0.0140), the answer is 0.0175.

Step3: Perform subtraction for 0.820 - 0.030

Subtract the two numbers: $0.820−0.030 = 0.790$.

Step4: Perform multiplication for (240900)(120.0)

Multiply the two numbers: $240900\times120.0 = 28908000$. In scientific notation and considering significant figures, $240900$ has 4 significant figures and $120.0$ has 4 significant figures. The result in scientific notation is $2.891\times 10^{7}$.

Step5: Perform division for 340/12.5

Divide the two numbers: $\frac{340}{12.5}=27.2$.

Step6: Perform multiplication for $(2.450\times 10^{6})(2.0\times 10^{6})$

Use the rule of exponents $a^{m}\times a^{n}=a^{m + n}$ and multiply the coefficients: $(2.450\times2.0)\times10^{6 + 6}=4.9\times 10^{12}$.

Step7: Perform division for $(5.369\times 10^{12})/(2.89\times 10^{7})$

Use the rule of exponents $\frac{a^{m}}{a^{n}}=a^{m - n}$ and divide the coefficients: $\frac{5.369}{2.89}\times10^{12-7}\approx1.86\times 10^{5}$.

Answer:

1. 325.2
2. 6018
3. 0.0175
4. 0.790
5. $2.891\times 10^{7}$
6. 27.2
7. $4.9\times 10^{12}$
8. $1.86\times 10^{5}$