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solve for b. 8 > \\frac{b}{-2}+1

Question

solve for b.
8 > \frac{b}{-2}+1

Explanation:

Step1: Subtract 1 from both sides

$8 - 1>\frac{b}{-2}+1 - 1$
$7>\frac{b}{-2}$

Step2: Multiply both sides by -2 and reverse the inequality sign

$7\times(-2)<\frac{b}{-2}\times(-2)$
$- 14 < b$

Answer:

$b > - 14$