Question

solve.\
-4x + 4y = -12\
-3x + 6y = 3\
(\square, \square)\
submit

Explanation:

Step1: Simplify the first equation

Divide the first equation \(-4x + 4y = -12\) by 4:
\(\frac{-4x}{4}+\frac{4y}{4}=\frac{-12}{4}\)
\(-x + y = -3\), which can be rewritten as \(y = x - 3\).

Step2: Substitute \(y = x - 3\) into the second equation

The second equation is \(-3x + 6y = 3\). Substitute \(y\) with \(x - 3\):
\(-3x + 6(x - 3) = 3\)
Expand the left - hand side: \(-3x+6x - 18 = 3\)
Combine like terms: \(3x-18 = 3\)

Step3: Solve for \(x\)

Add 18 to both sides of the equation \(3x - 18=3\):
\(3x-18 + 18=3 + 18\)
\(3x=21\)
Divide both sides by 3: \(x=\frac{21}{3}=7\)

Step4: Solve for \(y\)

Substitute \(x = 7\) into \(y=x - 3\):
\(y=7 - 3=4\)

Answer:

\((7,4)\)