Question

solve for s.
-6s > -3s + 6
if there are no solutions, enter none.
enter the solution in interval notation. if no solution exists, enter none.

Explanation:

Step1: Add $3s$ to both sides

$-6s + 3s > -3s + 3s + 6$
$\implies -3s > 6$

Step2: Divide by $-3$, reverse inequality

$\frac{-3s}{-3} < \frac{6}{-3}$
$\implies s < -2$

Step3: Write in interval notation

All real numbers less than $-2$ correspond to the interval $(-\infty, -2)$

Answer:

$(-\infty, -2)$