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solve for n. 11(n - 1) + 35 = 3n \\bigcirc n = -6 \\bigcirc n = -3 \\bi…

Question

solve for n.
11(n - 1) + 35 = 3n
\bigcirc n = -6
\bigcirc n = -3
\bigcirc n = 3
\bigcirc n = 6

Explanation:

Step1: Expand the left side

Using the distributive property \(a(b - c)=ab - ac\), we have \(11(n - 1)=11n-11\). So the equation becomes \(11n - 11+35 = 3n\).

Step2: Simplify the left side

Combine like terms: \(-11 + 35=24\), so the equation is \(11n+24 = 3n\).

Step3: Subtract \(11n\) from both sides

\(11n+24-11n = 3n-11n\), which simplifies to \(24=-8n\).

Step4: Solve for \(n\)

Divide both sides by \(-8\): \(\frac{24}{-8}=\frac{-8n}{-8}\), so \(n = - 3\).

Answer:

B. \(n=-3\)