Question

solve ((v + 1)^2 - 40 = 0), where (v) is a real number. simplify your answer as much as possible. if there is more than one solution, separate them with commas. if there is no solution, click
o solution.\ (v=square)

Explanation:

Step1: Isolate the squared term

Add 40 to both sides.
$$(v+1)^2 = 40$$

Step2: Take square roots of both sides

Use square root property for equations.
$$v+1 = \pm\sqrt{40}$$

Step3: Simplify the square root

Factor 40 into $4 \times 10$.
$$\sqrt{40} = \sqrt{4 \times 10} = 2\sqrt{10}$$

Step4: Solve for v

Subtract 1 from both sides.
$$v = -1 \pm 2\sqrt{10}$$

Answer:

$v = -1 + 2\sqrt{10}, -1 - 2\sqrt{10}$